{VERSION 5 0 "IBM INTEL NT" "5.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 2 0 0 0 2 0 0 0 0 0 0 1 }{CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 256 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 257 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 258 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 259 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 260 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 261 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 262 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 263 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 264 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 265 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 266 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 267 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 268 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 269 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 270 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 271 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 272 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 273 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 274 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 275 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 276 "" 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 }{PSTYLE "Normal " -1 0 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Text Output" -1 2 1 {CSTYLE "" -1 -1 "Courier" 1 10 0 0 255 1 0 0 0 0 0 1 3 0 3 1 }1 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Warning" 2 7 1 {CSTYLE "" -1 -1 "" 0 1 0 0 255 1 0 0 0 0 0 0 1 0 0 1 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Error" 7 8 1 {CSTYLE "" -1 -1 "" 0 1 255 0 255 1 0 0 0 0 0 0 0 0 0 1 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Output" 0 11 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }3 3 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Plot" 0 13 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "" 0 256 1 {CSTYLE "" -1 -1 "" 1 16 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }} {SECT 0 {EXCHG {PARA 256 "" 0 "" {TEXT 256 25 "The mathematical pendul um" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 102 "We follow Gerd Baumann's approach in Mathematica to determine the period of the mathematical pendulum." }}{PARA 0 "" 0 "" {TEXT -1 165 "First, we write down the kinetic and potential energies: the kinetic energy \+ is expressed in terms of the angular velocity and the moment of inerti a for a point mass " }{TEXT 274 1 "m" }{TEXT -1 23 " suspended at dist ance " }{TEXT 273 1 "l" }{TEXT -1 1 "." }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 43 "We call the angular velocity d/dt phi=omega" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 24 "Tkin:=1/2*m*l^2*omega^2;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%TkinG,$*(%\"mG\"\"\")%\"lG\"\"#F()%&omegaGF+F(#F(F+ " }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 77 "The potential energy follows \+ from the height of the pendulum bob (point mass " }{TEXT 275 1 "m" } {TEXT -1 74 "). We choose the potential energy to be zero if the mass \+ is at the bottom." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 25 "Upot:= m*g*l*(1-cos(phi));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%UpotG**%\"mG \"\"\"%\"gGF'%\"lGF',&F'F'-%$cosG6#%$phiG!\"\"F'" }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 51 "For plotting we have to pick some parameter values :" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 5 "l:=1;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"lG\"\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 6 "g:=10;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"gG\"#5" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 5 "m:=1;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"mG\"\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 141 "plots[contourplot](Tkin+Upot,phi=-3/2*Pi..3/2*Pi,omega=-10..10,co ntours=[1,5,9,13,17,21,25,29],axes=boxed,filled=true, coloring=[red,gr een]);" }}{PARA 13 "" 1 "" {GLPLOT2D 400 300 300 {PLOTDATA 2 "66-%'CUR VESG6\\s7$7$$!3!*zYQ!)*)Q7Z!#<$!3-%)*******\\i:'F*7$$!3c&*=9V^bpYF*$!3 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%Q!)*)Q7ZFc^fl;Facz$\"#5FK" 1 2 0 1 10 0 2 9 1 2 2 1.000000 45.000000 45.000000 0 0 "Curve 1" "Curve 2" "Curve 3" "Curve 4" "Curve 5" "Curve 6" "Curve 7" "Curve 8" "Curve 9" "Curve 10" "Curve 11" "Curve 12" "Cu rve 13" "Curve 14" "Curve 15" "Curve 16" "Curve 17" }}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 547 "This phase space diagram is obviously periodic with period 2 Pi. For small angular velocities one has a system appro ximated by a harmonic oscillator, while for larger velocites (or energ ies, i.e., higher contours) one has solutions that simply revolve (win ding the pendulum; in the periodic phase space diagrams one leaves e.g ., at the right to re-enter at the same angular velocity at the left. \+ The motion is left to right in the top half (for the open curves), and right to the left in the bottom half (look at the sign of the angular velocity)." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 115 "The regularity of the diagram is very striking. The units of e nergy (chosen for the contour lines) are in MKSA, if " }{TEXT 259 1 "l " }{TEXT -1 1 "," }{TEXT 258 1 "g" }{TEXT -1 1 "," }{TEXT 257 1 "m" } {TEXT -1 19 " are given in MKSA." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }} {PARA 0 "" 0 "" {TEXT -1 358 "There is a critical energy where the sep aration occurs between oscillating solutions (closed contours, in the \+ somewhat abstract phase space one obtains elliptic or deformed ellipti c 'trajectories'; translate those into oscillations using your imagina tion, by watching the sign of omega, passage through phi=0, i.e., the \+ bottom position of the pendulum, etc.)" }}{PARA 0 "" 0 "" {TEXT -1 0 " " }}{PARA 0 "" 0 "" {TEXT -1 229 "The locations phi=+Pi, omega=0, or p hi=-Pi, omega=0 correspond to the unstable equilibrium (pendulum at th e top at rest). One can show that the phase-space 'trajectory' become \+ a cosine curves of phi/2 [Marion-Thornton, eq. 4.31]." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 385 "For winding solutions we observe how their angular velocity is modulated as the go through \+ the (periodic) potential well. For sufficiently high energies (not sho wn) the phase space 'trajectories' approach straigh lines, as the pend ulum bob's kinetic energy is so high that the variation in the potenti al energy (by being moved up and down in the graviational field) becom es negligible." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 298 "Time-dependent perturbations of the pendulum by an exter nal force can lead to a loss of regularity in the phase space diagram \+ (CHAOS). The modulation can come from a simple coupling to a second pe ndulum, which leads to a time-varying support point (science museum de monstrations + classroom demo!)." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }} {PARA 0 "" 0 "" {TEXT -1 102 "The determination of the phase-space 'tr ajectories' was easy. The actual integration of phi(t) is not!" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 145 "The total energy can be expressed through the potential energy at the turning point (pendulum bob at re st), i.e., through the initial angle phi0." }}{PARA 0 "" 0 "" {TEXT -1 77 "One introduces the energy parameter (initial phase angle phi0) \+ k=sin(phi0/2);" }}{PARA 0 "" 0 "" {TEXT -1 135 "To recover the general expression for the potential energy we unassign the parameters for le ngth, gravitational acceleration, and mass:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 29 "l:='l': g:='g': m:='m': Upot;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#**%\"mG\"\"\"%\"gGF%%\"lGF%,&F%F%-%$cosG6#%$phiG!\"\"F% " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 46 "Upot:=algsubs(cos(phi)= 1-2*sin(phi/2)^2,Upot);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%UpotG,$* *%\"mG\"\"\"%\"gGF(%\"lGF()-%$sinG6#,$%$phiG#F(\"\"#F2F(F2" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 26 "Etot:=subs(phi=phi0,Upot);" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%%EtotG,$**%\"mG\"\"\"%\"gGF(%\"lGF() -%$sinG6#,$%%phi0G#F(\"\"#F2F(F2" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 61 "The total energy for a given trajectory thus depends only on " } {TEXT 261 1 "k" }{TEXT -1 66 "=sin(phi/2). Therefore, the period is ca lculated as a function of " }{TEXT 260 1 "k" }{TEXT -1 1 "." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 145 "To calculate t he period for the oscillatory solutions, one uses the energy expressio n which depends on phi and omega=diff(phi,t), isolates omega." }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 15 "Tkin+Upot=Etot;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/,&*(%\"mG\"\"\")%\"lG\"\"#F')%&omegaGF*F'#F'F* *,F*F'F&F'%\"gGF'F)F')-%$sinG6#,$%$phiGF-F*F'F',$**F&F'F/F'F)F')-F26#, $%%phi0GF-F*F'F*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 15 "solve(% ,omega);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6$,$*&%\"lG!\"\"*(F%\"\"\"% \"gGF(,&*$)-%$sinG6#,$%$phiG#F(\"\"#F3F(F&*$)-F.6#,$%%phi0GF2F3F(F(F(F 2F3,$F$!\"#" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 41 "DE:=diff(phi (t),t)=subs(phi=phi(t),%[1]);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#DE G/-%%diffG6$-%$phiG6#%\"tGF,,$*&%\"lG!\"\"*(F/\"\"\"%\"gGF2,&*$)-%$sin G6#,$F)#F2\"\"#F " 0 "" {MPLTEXT 1 0 37 "sol:=dsolve(\{DE,phi(0)=phi0\},phi(t));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$solG/-%$phiG6#%\"tG-%'RootOfG6#,( F)\"\"#-%$IntG6$*&%\"lG\"\"\"-%%sqrtG6#,$*&F4F4*(,&-%$cosG6#%#_aG!\"\" -F=6#%%phi0GF4F4F3F4%\"gGF4F@!\"#F4/F?;\"\"!%#_ZGF@-F06$*(F3F4-F66#F.F 4-F66#*&F4F4*(,&F " 0 "" {MPLTEXT 1 0 32 "subs(diff(phi(t),t)=dphi/dt,DE);" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#/*&%%dphiG\"\"\"%#dtG!\"\",$*&%\"lGF(* (F+F&%\"gGF&,&*$)-%$sinG6#,$-%$phiG6#%\"tG#F&\"\"#F:F&F(*$)-F26#,$%%ph i0GF9F:F&F&F&F9F:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "solve( %,dt);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,$*(%%dphiG\"\"\"%\"lGF&,$*( F'F&%\"gGF&,&*$)-%$sinG6#,$-%$phiG6#%\"tG#F&\"\"#F7F&F&*$)-F/6#,$%%phi 0GF6F7F&!\"\"F&F>#F>F7F6" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 203 "If w e integrate the right-hand side over phi from 0 to phi0, the left-hand side will give us a quarter of the period T (for the full period phi \+ would have to continue through 0 to -phi0 and back to phi0." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 71 "The integral to be carried out falls into a category known as elliptic." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "assume(k>0);" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 61 "A required integral can be expressed as an elliptic \+ function:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 40 "Int(1/sqrt((1- z^2)*(1-k^2*z^2)),z=0..1);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#-%$IntG6 $*&\"\"\"F'*$-%%sqrtG6#*&,&F'F'*$)%\"zG\"\"#F'!\"\"F',&F'F'*&)%#k|irGF 1F'F/F'F2F'F'F2/F0;\"\"!F'" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "value(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#*&%#k|irG!\"\"-%*Ellip ticFG6$F$*&\"\"\"F*F$F%F*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "omega[0]:=sqrt(g/l);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>&%&omegaG 6#\"\"!*$-%%sqrtG6#*&%\"gG\"\"\"%\"lG!\"\"F." }}}{EXCHG {PARA 0 "" 0 " " {TEXT -1 76 "To help Maple we restrict the inital phase to be positi ve, and less than Pi." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "as sume(phi0>0,phi0 " 0 "" {MPLTEXT 1 0 66 "T: =2/omega[0]*Int(1/sqrt(sin(phi0/2)^2-sin(phi/2)^2),phi=0..phi0);" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"TG,$*&*&%\"gG\"\"\"%\"lG!\"\"#F+\" \"#-%$IntG6$*&F)F)*$-%%sqrtG6#,&*$)-%$sinG6#,$%$phiG#F)F-F-F)F+*$)-F:6 #,$%&phi0|irGF>F-F)F)F)F+/F=;\"\"!FDF)F-" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "T:=value(T);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"T G,$*&*&%\"gG\"\"\"%\"lG!\"\"#F+\"\"#-%*EllipticKG6#-%$sinG6#,$%&phi0|i rG#F)F-F)\"\"%" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 126 "For plotting p urposes let us simplify matters by chosing the pendulum length and the gravitational acceleration in MKSA units:" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 13 "g:=10; l:=10;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>% \"gG\"#5" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"lG\"#5" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 2 "T;" }}{PARA 11 "" 1 "" {XPPMATH 20 " 6#,$-%*EllipticKG6#-%$sinG6#,$%&phi0|irG#\"\"\"\"\"#\"\"%" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 67 "We now explore this answer as a function \+ of the initial angle phi0:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "plot(T,phi0=0..Pi);" }}{PARA 13 "" 1 "" {GLPLOT2D 696 243 243 {PLOTDATA 2 "6%-%'CURVESG6$7ao7$$\"\"!F)$\"+3`=$G'!\"*7$$\"+LzxZo!#6$ \"+[s-&G'F,7$$\"+!H*f!G\"!#5$\"+s8j*G'F,7$$\"+xGm]>F6$\"++0;)H'F,7$$\" +#3o^i#F6$\"+KbN5jF,7$$\"+![nkH$F6$\"+3j7EjF,7$$\"+bz%)=RF6$\"+!eHSM'F ,7$$\"+()oGjXF6$\"+W%[fO'F,7$$\"+`lwH_F6$\"+!3/BR'F,7$$\"+4)3T*eF6$\"+ #z*QAkF,7$$\"+ykYxlF6$\"+;LTdkF,7$$\"+&Go$zrF6$\"+%e#y\"\\'F,7$$\"+gr' p&yF6$\"+#HVX`'F,7$$\"+?$[t`)F6$\"+G['>e'F,7$$\"+S;-$>*F6$\"+%=!3KmF,7 $$\"+HeV)y*F6$\"+CV\\\"o'F,7$$\"+*3W'\\5F,$\"+[/IXnF,7$$\"+/9i46F,$\"+ +v$Q!oF,7$$\"+\"G*Qz6F,$\"+s+PxoF,7$$\"+tc9T7F,$\"+?PfZpF,7$$\"+BA!*38 F,$\"+Gm]IqF,7$$\"+#[AMP\"F,$\"+%o.b6(F,7$$\"+.EuS9F,$\"+#R#)3@(F,7$$ \"+!\\jD]\"F,$\"+O2*[I(F,7$$\"+ocCp:F,$\"+gMn8uF,7$$\"+5(4&Q;F,$\"+!)z RNvF,7$$\"+iU!))p\"F,$\"+S%z\"\\wF,7$$\"+IS#Rw\"F,$\"+?l#4y(F,7$$\"+B \"*>J=F,$\"+WbaFzF,7$$\"+wY,(*=F,$\"+w7J#3)F,7$$\"+3Ypg>F,$\"+k]zV#)F, 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10 0 2 9 1 4 2 1.000000 45.000000 45.000000 0 0 "Curve 1" }}}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "taylor(T,phi0=0,5);" }}{PARA 11 "" 1 "" {XPPMATH 20 " 6#++%&phi0|irG,$%#PiG\"\"#\"\"!,$F&#\"\"\"\"\")F',$F&#\"#6\"%O:\"\"%-% \"OG6#F+\"\"'" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 29 "T1:=algsub s(sin(phi0/2)=k,T);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#T1G,$-%*Elli pticKG6#%#k|irG\"\"%" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 17 "ser ies(T1,k=0,8);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#+-%#k|irG,$%#PiG\"\" #\"\"!,$F&#\"\"\"F'F',$F&#\"\"*\"#K\"\"%,$F&#\"#D\"$G\"\"\"'-%\"OG6#F+ \"\")" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 24 "T1t:=convert(%,pol ynom);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$T1tG,*%#PiG\"\"#*(#\"\"\" F'F*F&F*)%#k|irGF'F*F**(#\"\"*\"#KF*F&F*)F,\"\"%F*F**(#\"#D\"$G\"F*F&F *)F,\"\"'F*F*" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 69 "This agrees with eq. 2.25 in Baumann (or analytical mechanics texts)." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 26 "plot(\{Re(T1),T1t\},k=0..1);" }} 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}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 59 "This does not work in Maple5! However, it does from 6.0 on." }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 22 "simplify(T2,symbolic);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,$-%*EllipticKG6#%#k|irG\"\"%" }}}{EXCHG {PARA 0 "" 0 " " {TEXT -1 132 "Maple is reluctant to carry out the cancellation of fu nction and its inverse. In Maple6 T2 is directly calculated as 4*Ellip ticK(k)." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 75 "A further exploration should look into the calculation of trajecto ries phi(" }{TEXT 270 1 "t" }{TEXT -1 2 ")!" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 376 "Before we proceed with this st ep we construct the phase diagram (a plot of the time derivative of th e dynamic variable [the phase angle phi] against the dynamic variable \+ itself. For this we need the energy expression (we will look at contou r lines of equal height, i.e. lines of constant energy, as the mechani cal energy is conserved for a frictionless mathematical pendulum)." }} }{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "l:='l': g:='g': m:='m':" }} }{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 11 "phi:='phi';" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$phiGF$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 3 "DE;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/-%%diffG6$-%$phiG6#%\"tGF *,$*&%\"lG!\"\"*(F-\"\"\"%\"gGF0,&*$)-%$sinG6#,$F'#F0\"\"#F:F0F.*$)-F6 6#,$%&phi0|irGF9F:F0F0F0F9F:" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 48 "L et us make use of Gerd Baumann's analytic work:" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 20 "omega[0]:=sqrt(g/l);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>&%&omegaG6#\"\"!*$-%%sqrtG6#*&%\"gG\"\"\"%\"lG!\"\"F. " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 5 "Etot;" }}{PARA 11 "" 1 " " {XPPMATH 20 "6#,$**%\"mG\"\"\"%\"gGF&%\"lGF&)-%$sinG6#,$%&phi0|irG#F &\"\"#F0F&F0" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 29 "E_s:=Etot/( m*l^2*omega[0]^2);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$E_sG,$*$)-%$s inG6#,$%&phi0|irG#\"\"\"\"\"#F/F.F/" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 255 "The scaled energy parameter allows to distinguish easily the d ifferent types of motion: for E_s<2 we have oscillations, for E_s>2 ro tations, and E_s=2 corresponds to the asymptotic solution where the pe ndulum bob remains in the unstable equilibrium point." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 55 "We express the scaled \+ energy in terms of the parameter " }{TEXT 263 1 "k" }{TEXT -1 13 "=sin (phi0/2):" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "k0:=7/8;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%#k0G#\"\"(\"\")" }}}{EXCHG {PARA 0 " > " 0 "" {MPLTEXT 1 0 12 "E_s:=2*k0^2;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$E_sG#\"#\\\"#K" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 11 " phi:='phi':" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 99 "We define the diff erential equation such that positive and negative angular velocities a re allowed." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 58 "DE:=(diff(ph i(t),t))^2=omega[0]^2*(2*(cos(phi(t))-1+E_s));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#DEG/*$)-%%diffG6$-%$phiG6#%\"tGF.\"\"#\"\"\"*(%\"gGF 0%\"lG!\"\",&-%$cosG6#F+F/#\"#<\"#;F0F0" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 69 "Oscillatory solutions to the equation of motion (E_s<2) a re given by:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 49 "theta:=(k,t )->2*arcsin(k*JacobiSN(omega[0]*t,k));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&thetaGf*6$%\"kG%\"tG6\"6$%)operatorG%&arrowGF),$-%'arcsinG6#* &9$\"\"\"-%)JacobiSNG6$*&&%&omegaG6#\"\"!F39%F3F2F3\"\"#F)F)F)" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "g:=10; l:=1;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"gG\"#5" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\" lG\"\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 28 "subs(phi(t)=the ta(k0,t),DE);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/*$)-%%diffG6$,$-%'ar csinG6#,$-%)JacobiSNG6$*&-%%sqrtG6#\"#5\"\"\"%\"tGF6#\"\"(\"\")F8\"\"# F7F;F6,&-%$cosG6#F)\"#?#\"#&)F:F6" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "simplify(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/,&*$ )-%)JacobiSNG6$*&-%%sqrtG6#\"#5\"\"\"%\"tGF/#\"\"(\"\")\"\"#F/#!$X#F3# \"$X#F3F/,&-%$cosG6#,$-%'arcsinG6#,$F'F1F4\"#?#\"#&)F3F/" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "evalf(subs(t=1,%));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/$\"*[\"H:y!\")$\"+w9H:y!\"*" }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 83 "Without further work Maple cannot figure out that \+ the expression written for theta(" }{TEXT 271 1 "t" }{TEXT -1 134 ") s olves the differential equation. 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Only for values of " }{TEXT 264 1 "k" }{TEXT -1 164 " close to unity do we see a qualtiative change in t he behaviour of the solution, i.e., a dramatic slowdown of the pendulu m bob in the vicinity of the turning point." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 99 "We can follow this up with an a nimation. To display the pendulum's motion we need to calculate the " }{TEXT 267 1 "x" }{TEXT -1 5 " and " }{TEXT 266 1 "y" }{TEXT -1 36 " c oordinates. We choose a length of " }{TEXT 268 1 "l" }{TEXT -1 99 "=1 \+ and define the coordinates such that the height is zero at the suspens ion point of the pendulum." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 68 "x:=(k,t)->evalf(sin(theta(k,t))): y:=(k,t)->-evalf(cos(theta(k,t)) ):" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "x(0.99,1),y(0.99,1); " }}{PARA 11 "" 1 "" {XPPMATH 20 "6$$\"+I\\)Q%G!#5$\"+V74(e*F%" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 50 "We draw lines from the origin to t he pendulum bob:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 151 "PL:=(k ,t)->plot([[0,0],[x(k,t),y(k,t)]],style=line,color=magenta,title=cat(c at(\"k= \",convert(evalf(k,3),string)),\"time= \",convert(evalf(t,3),s tring))):" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 36 "PLs:=seq(PL(0. 995,it/10),it=1..200):" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "w ith(plots):" }}{PARA 7 "" 1 "" {TEXT -1 50 "Warning, the name changeco ords has been redefined\n" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 60 "display(PLs,insequence=true,axes=boxed,scaling=constrained);" }} {PARA 13 "" 1 "" {GLPLOT2D 400 300 300 {PLOTDATA 2 "6%-%(ANIMATEG6dw7& -%'CURVESG6%7$7$$\"\"!F-F,7$$\"3Y*****H4\"o-e!#=$!3C+++h^DW\")F1-%'COL OURG6&%$RGBG$\"*++++\"!\")F,F8-%&STYLEG6#%%LINEG-%+AXESLABELSG6$Q!6\"F B-%&TITLEG6#Q2k=~.995time=~.100FC-%%VIEWG6$%(DEFAULTGFK7&-F(6%7$F+7$$ \"3a******fBAa#*F1$!31+++TdP*y$F1F4F;F?-FE6#Q2k=~.995time=~.200FCFH7&- F(6%7$F+7$$\"3G+++FL`k**F1$\"36+++7Fs9%)!#>F4F;F?-FE6#Q2k=~.995time=~. 300FCFH7&-F(6%7$F+7$$\"3#******>6D`'*)F1$\"3.+++7%z(HWF1F4F;F?-FE6#Q2k =~.995time=~.400FCFH7&-F(6%7$F+7$$\"3i******4kzatF1$\"3O+++K#oax'F1F4F ;F?-FE6#Q2k=~.995time=~.500FCFH7&-F(6%7$F+7$$\"3_*****R5/^w&F1$\"3G+++ L!)*3<)F1F4F;F?-FE6#Q2k=~.995time=~.600FCFH7&-F(6%7$F+7$$\"3=+++Y$fJW% F1$\"3a+++P;qe*)F1F4F;F?-FE6#Q2k=~.995time=~.700FCFH7&-F(6%7$F+7$$\"3( ******f(f,RMF1$\"39+++Gp0!R*F1F4F;F?-FE6#Q2k=~.995time=~.800FCFH7&-F(6 %7$F+7$$\"3!)*****>Wz&GFF1$\"3*)*****RMV0i*F1F4F;F?-FE6#Q2k=~.995time= ~.900FCFH7&-F(6%7$F+7$$\"37+++bY_rAF1$\"3[+++#3#fQ(*F1F4F;F?-FE6#Q0k=~ .995time=~1.FCFH7&-F(6%7$F+7$$\"38+++^;6M?F1$\"3_*****41M4z*F1F4F;F?-F E6#Q2k=~.995time=~1.10FCFH7&-F(6%7$F+7$$\"3%******R)Q%o*>F1$\"3U+++\"o -')z*F1F4F;F?-FE6#Q2k=~.995time=~1.20FCFH7&-F(6%7$F+7$$\"3-+++kHbc@F1$ \"3Y+++dbpk(*F1F4F;F?-FE6#Q2k=~.995time=~1.30FCFH7&-F(6%7$F+7$$\"3;+++ SahEDF1$\"3')*****4CZbn*F1F4F;F?-FE6#Q2k=~.995time=~1.40FCFH7&-F(6%7$F +7$$\"3y*****f\"H\"e8$F1$\"31+++&e8c\\*F1F4F;F?-FE6#Q2k=~.995time=~1.5 0FCFH7&-F(6%7$F+7$$\"3))*****\\J@N-%F1$\"3e*****\\()\\[:*F1F4F;F?-FE6# Q2k=~.995time=~1.60FCFH7&-F(6%7$F+7$$\"3X*****HYcVA&F1$\"3D+++wryE&)F1 F4F;F?-FE6#Q2k=~.995time=~1.70FCFH7&-F(6%7$F+7$$\"32+++[`!os'F1$\"3]** ***>OI$*R(F1F4F;F?-FE6#Q2k=~.995time=~1.80FCFH7&-F(6%7$F+7$$\"35+++w6g y$)F1$\"3')******4*\\)eaF1F4F;F?-FE6#Q2k=~.995time=~1.90FCFH7&-F(6%7$F +7$$\"32+++J[B<(*F1$\"3-+++?t@hBF1F4F;F?-FE6#Q0k=~.995time=~2.FCFH7&-F (6%7$F+7$$\"3@+++y9)o!)*F1$!3)*******p+yb>F1F4F;F?-FE6#Q2k=~.995time=~ 2.10FCFH7&-F(6%7$F+7$$\"3y*****z-lXY(F1$!31+++6@MamF1F4F;F?-FE6#Q2k=~. 995time=~2.20FCFH7&-F(6%7$F+7$$\"31+++-$R'pBF1$!3?+++&[%=:(*F1F4F;F?-F E6#Q2k=~.995time=~2.30FCFH7&-F(6%7$F+7$$!3#******4eKUx$F1$!3g*****Hl3/ E*F1F4F;F?-FE6#Q2k=~.995time=~2.40FCFH7&-F(6%7$F+7$$!3O+++Hx)zG)F1$!3# )*****\\vnaf&F1F4F;F?-FE6#Q2k=~.995time=~2.50FCFH7&-F(6%7$F+7$$!3-+++r 6Zk**F1$!3`*****>')z?U)F[oF4F;F?-FE6#Q2k=~.995time=~2.60FCFH7&-F(6%7$F +7$$!3Y*****ff\"))o%*F1$\"36+++\"yIc@$F1F4F;F?-FE6#Q2k=~.995time=~2.70 FCFH7&-F(6%7$F+7$$!3K+++p(\\)*)zF1$\"3N+++Z)4N,'F1F4F;F?-FE6#Q2k=~.995 time=~2.80FCFH7&-F(6%7$F+7$$!3;+++falYjF1$\"3[*****fLpys(F1F4F;F?-FE6# Q2k=~.995time=~2.90FCFH7&-F(6%7$F+7$$!3)******HrI'4\\F1$\"3K+++ZQ!=r)F 1F4F;F?-FE6#Q0k=~.995time=~3.FCFH7&-F(6%7$F+7$$!3%******fZ)*\\y$F1$\"3 [+++MN,c#*F1F4F;F?-FE6#Q2k=~.995time=~3.10FCFH7&-F(6%7$F+7$$!3#****** \\*fDnHF1$\"3-+++Ryi\\&*F1F4F;F?-FE6#Q2k=~.995time=~3.20FCFH7&-F(6%7$F +7$$!3'******zaT#=CF1$\"3=+++14?.(*F1F4F;F?-FE6#Q2k=~.995time=~3.30FCF H7&-F(6%7$F+7$$!3-+++`bF+@F1$\"3w******oY&px*F1F4F;F?-FE6#Q2k=~.995tim e=~3.40FCFH7&-F(6%7$F+7$$!3)******Hh5!))>F1$\"3'******\\l)R+)*F1F4F;F? 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(6%7$F+7$$\"3++++uE[)G#F1$\"3\"******H0@Yt*F1F4F;F?-FE6#Q2k=~.995time= ~19.7FCFH7&-F(6%7$F+7$$\"3))*****>$o%4/#F1$\"3O+++K:^*y*F1F4F;F?-FE6#Q 2k=~.995time=~19.8FCFH7&-F(6%7$F+7$$\"3)*******GZ8%*>F1$\"3m*****fQa\" *z*F1F4F;F?-FE6#Q2k=~.995time=~19.9FCFH7&-F(6%7$F+7$$\"35+++gz1W@F1$\" 3))*****p_Wuw*F1F4F;F?-FE6#Q1k=~.995time=~20.FCFH-%*AXESSTYLEG6#%$BOXG -%(SCALINGG6#%,CONSTRAINEDG" 1 2 0 1 10 0 2 9 1 2 1 1.000000 37.000000 44.000000 0 0 "Curve 1" }}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 231 "The slowdown of the pendulum bob as the top position is approache d is very obvious. Thus the lack of isochronicity, or the dependence o f the period on the maximum amplitude (energy deposited into the pendu lum) is made very obvious." }}{PARA 0 "" 0 "" {TEXT -1 298 "In Maple 6 the title for each frame is actually displayed in the animation. Howe ver, we found two errors for Maple 6.0 in this worksheet: 1) the conto urplot is wrong; 2) the numerical evaluation of the JacobiSN functions is in error. We can only hope that a service pack will remedy these p roblems." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 215 "While the demonstration of Maple's handling of elliptic \+ integrals has been impressive, we wish to demonstrate also a general a pproach that can be applied to any differential equation, namely the n umerical solution. " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 63 "DE:= k->(diff(phi(t),t))^2=omega[0]^2*(2*(cos(phi(t))-1+2*k^2));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#DEGf*6#%\"kG6\"6$%)operatorG%&arrowGF(/*$ )-%%diffG6$-%$phiG6#%\"tGF5\"\"#\"\"\"*&)&%&omegaG6#\"\"!F6F7,(-%$cosG 6#F2F6F6!\"\"*&\"\"%F7)9$F6F7F7F7F(F(F(" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "omega[0]:=1;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>&%&o megaG6#\"\"!\"\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 13 "IC:=p hi(0)=0;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#ICG/-%$phiG6#\"\"!F)" } }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 43 "sol:=dsolve(\{DE(0.999),IC \},phi(t),numeric);" }}{PARA 8 "" 1 "" {TEXT -1 83 "Error, (in DEtools /convertsys) unable to convert to an explicit first-order system\n" }} }{EXCHG {PARA 0 "" 0 "" {TEXT -1 125 "Bad news! We need to go back to \+ the original Newton law. Maple 6 is, however, improved in this area. M aple 7 can't handle it." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 90 " omega:='omega': # it is not good to mix omega(t), and omega[0], which \+ makes omega a table." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 64 "DE: =diff(phi(t),t)=omega(t),diff(omega(t),t)=-(g/l)*sin(phi(t));" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%#DEG6$/-%%diffG6$-%$phiG6#%\"tGF--%& omegaGF,/-F(6$F.F-,$-%$sinG6#F*!#5" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 94 "The initial condition is chosen to be the turning point, where \+ all energy is in the potential." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "phifun:=k->2*arcsin(k);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%' phifunGf*6#%\"kG6\"6$%)operatorG%&arrowGF(,$-%'arcsinG6#9$\"\"#F(F(F( " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "phi0:=phifun(0.999);" } }{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%phi0G$\"+![U@0$!\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 27 "IC:=omega(0)=0,phi(0)=phi0;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%#ICG6$/-%&omegaG6#\"\"!F*/-%$phiGF)$ \"+![U@0$!\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 68 "sol:=dsolv e(\{DE,IC\},[omega(t),phi(t)],numeric,output=listprocedure);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$solG7%/%\"tGf*6#F'6\"6#%aoCopyright~(c)~1 993~by~the~University~of~Waterloo.~All~rights~reserved.GF*9$F*F*F*/-%& omegaGF)f*F)6&%$resG%*plistprocG%)outpointG%&ndsolG6#%inCopyright~(c)~ 2000~by~Waterloo~Maple~Inc.~All~rights~reserved.GF*C'>8&-%&evalfG6#F-> 8%f*6#%(rkf45_xG6.%\"iG%/comp_soln_dataG%(odeprocG%&icvecG%(LR_caseG% \"YG%$valGF5%#ptG%*stop_procG%+stop_arrayG%&cplexG6#%aoCopyright~(c)~2 000~by~the~University~of~Waterloo.~All~rights~reserved.GE\\s#Q0soln_pr oceduresF*7%\")#*f^;\")%QOc\"\")W\"Qd\"Q(complexF*%&falseGC2@$-%'membe rG6$F-7$Q4left_comp_soln_dataF*Q5right_comp_soln_dataF*O\"\"!@$2%'Digi tsG-%&truncG6#-%'evalhfG6#F`o>F`oFao>8+F<@$4-%%typeG6$Fio.%(numericG@% -Fgn6$Fio7%Q&startF*Q%leftF*Q&rightF*O$F]oF]oO-.9!F>>F;f*6&%\"NGF'%\"Y G%#YPGF*6#%A[Y[1]~=~omega(t),~Y[2]~=~phi(t)]GF*C$>&9'6#\"\"\",$-%$sinG 6#&9&6#\"\"#!#5>&FiqFbr&FarFjqF*F*F*>8'=F*6#;F[rFcrE\\[l#F[rFipFcr$\"+ ![U@0$!\"*>8-F]o>8.F]o>8)-%$mapG6$%$rhsG-%&parseG6#-%#opG6$\"\"$-%%eva lG6#F;>8/-F]q6#FX@'/FioFipO7$/F'Fio-%$seqG6$/&Ffs6#8$-F=6#&FirFcu/Fdu; F[r-%%nopsG6#Ffs1FipFio>8(F[o>F_vFjn>F@-F]q6#F_v@%4-F]p6$7#F@7#.%%list GC%Z%>F@-%;dsolve/numeric/SC/IVPsolveG6)F;;FipFioFirFbsFdsFft/%'scproc GFYF*C&@$/Fft%%trueGYF*>FftFhw>F@F_w>FgtFhw>8*&&F@6#Fat6#&F@Fbr>FbvF@C $>F^xF_x@$53/F_vF[o2F^xFio3/F_vFjn2FioF^xC&@$5/&F@6#\"\")F[r2\"#5FcyC$ >F^xF_x@%FjxY6$QQcannot~evaluate~the~solution~further~right~of~%1F*-&F =Fdy6#F^xY6$QPcannot~evaluate~the~solution~further~left~of~%1F*F^zZ%>F @-%F ftFhw>F@Ffz>FgtFhw>FbvF@>F^xF_x@&FjxC$@$33/%:_Env_smart_dsolve_numeric GFhw2FipF^x2-F]q6#FgpF^x>Fj[lF^x@$F[y@)/&FbvFdyF[rY6$Qcocannot~evaluat e~the~solution~further~right~of~%1,~probably~a~singularityF*F^z/F`\\lF crY6$Qcqcannot~evaluate~the~solution~further~right~of~%1,~maxfun~limit ~exceeded~(see~?dsolve,maxfun~for~details)F*F^z2FgyF`\\lC$@$0%7_Env_ds olve_nowarnstopGFhw-%(WARNINGG6#-_%,StringToolsG%.FormatMessageG6%Qhoc annot~evaluate~the~solution~further~right~of~%1,~stop~condition~#%2~vi olatedF*F^z,&F`\\lF[rFgy!\"\">FioF^xYF\\zF]yC$@$33Ff[l2F^xFip2F^x-F]q6 #Ffp>F`^lF^x@$F^y@)F_\\lY6$Qbocannot~evaluate~the~solution~further~lef t~of~%1,~probably~a~singularityF*F^zFd\\lY6$Qbqcannot~evaluate~the~sol ution~further~left~of~%1,~maxfun~limit~exceeded~(see~?dsolve,maxfun~fo r~details)F*F^zFh\\lC$@$F[]l-F^]l6#-Fa]l6%Qgocannot~evaluate~the~solut ion~further~left~of~%1,~stop~condition~#%2~violatedF*F^zFf]l>FioF^xYFb z>F^x-%9dsolve/numeric/SC/IVPvalG6$F@Fio7$F]u-F_u6$/Fbu&F^xFcuFhuF*F*F *@$4-F]p6$F;F_p@)-Fgn6$F;FdpO-F@F>/F;Q.procedurelistF*O-Fct6#F@0F]q%(u nknownGOF[qC$>Fir-%(pointtoG6#&-F@6#FSFbrO-.FirF>>Fdu7#-%*traperrorG6# Fe`l@%-F]p6$&FduFjq%'stringGY-F_tFcu-Fjs6#&FablFbrF*F*F*/-%$phiGF)f*F) F2F7F*C'>F;F<>F@FA@$F^`l@)Fb`lOFe`lFf`lOFi`lF[alOF[qC$>Fir-Faal6#&Fdal FaxOFgal>FduFjal@%F_blYFdbl-Fjs6#&FablFaxF*F*F*" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 24 "theta:=subs(sol,phi(t));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&thetaGf*6#%\"tG6&%$resG%*plistprocG%)outpointG%&ndso lG6#%inCopyright~(c)~2000~by~Waterloo~Maple~Inc.~All~rights~reserved.G 6\"C'>8&-%&evalfG6#9$>8%f*6#%(rkf45_xG6.%\"iG%/comp_soln_dataG%(odepro cG%&icvecG%(LR_caseG%\"YG%$valGF+%#ptG%*stop_procG%+stop_arrayG%&cplex G6#%aoCopyright~(c)~2000~by~the~University~of~Waterloo.~All~rights~res erved.GE\\s#Q0soln_proceduresF/7%\")#*f^;\")%QOc\"\")W\"Qd\"Q(complexF /%&falseGC2@$-%'memberG6$F67$Q4left_comp_soln_dataF/Q5right_comp_soln_ dataF/O\"\"!@$2%'DigitsG-%&truncG6#-%'evalhfG6#Fhn>FhnFin>8+F3@$4-%%ty peG6$Fao.%(numericG@%-FU6$Fao7%Q&startF/Q%leftF/Q&rightF/O$FenFenO-.9! F5>F2f*6&%\"NGF'%\"YG%#YPGF/6#%A[Y[1]~=~omega(t),~Y[2]~=~phi(t)]GF/C$> &9'6#\"\"\",$-%$sinG6#&9&6#\"\"#!#5>&FaqFjq&FiqFbqF/F/F/>8'=F/6#;FcqF[ rE\\[l#FcqFapF[r$\"+![U@0$!\"*>8-Fen>8.Fen>8)-%$mapG6$%$rhsG-%&parseG6 #-%#opG6$\"\"$-%%evalG6#F2>8/-Fep6#FP@'/FaoFapO7$/F'Fao-%$seqG6$/&F^s6 #8$-F46#&FarF[u/F\\u;Fcq-%%nopsG6#F^s1FapFao>8(FY>FguFX>F8-Fep6#Fgu@%4 -Feo6$7#F87#.%%listGC%Z%>F8-%;dsolve/numeric/SC/IVPsolveG6)F2;FapFaoFa rFjrF\\sF^t/%'scprocGFQF/C&@$/F^t%%trueGYF/>F^tF`w>F8Fgv>F_tF`w>8*&&F8 6#Fis6#&F8Fjq>FjuF8C$>FfwFgw@$53/FguFY2FfwFao3/FguFX2FaoFfwC&@$5/&F86# \"\")Fcq2\"#5F[yC$>FfwFgw@%FbxY6$QQcannot~evaluate~the~solution~furthe r~right~of~%1F/-&F4F\\y6#FfwY6$QPcannot~evaluate~the~solution~further~ left~of~%1F/FfyZ%>F8-%F^tF`w>F8F^z>F_tF`w>FjuF8>FfwFgw@&FbxC$@$33/%:_Env_ smart_dsolve_numericGF`w2FapFfw2-Fep6#F_pFfw>Fb[lFfw@$Fcx@)/&FjuF\\yFc qY6$Qcocannot~evaluate~the~solution~further~right~of~%1,~probably~a~si ngularityF/Ffy/Fh[lF[rY6$Qcqcannot~evaluate~the~solution~further~right ~of~%1,~maxfun~limit~exceeded~(see~?dsolve,maxfun~for~details)F/Ffy2F_ yFh[lC$@$0%7_Env_dsolve_nowarnstopGF`w-%(WARNINGG6#-_%,StringToolsG%.F ormatMessageG6%Qhocannot~evaluate~the~solution~further~right~of~%1,~st op~condition~#%2~violatedF/Ffy,&Fh[lFcqF_y!\"\">FaoFfwYFdyFexC$@$33F^[ l2FfwFap2Ffw-Fep6#F^p>Fh]lFfw@$Ffx@)Fg[lY6$Qbocannot~evaluate~the~solu tion~further~left~of~%1,~probably~a~singularityF/FfyF\\\\lY6$Qbqcannot ~evaluate~the~solution~further~left~of~%1,~maxfun~limit~exceeded~(see~ ?dsolve,maxfun~for~details)F/FfyF`\\lC$@$Fc\\l-Ff\\l6#-Fi\\l6%Qgocanno t~evaluate~the~solution~further~left~of~%1,~stop~condition~#%2~violate dF/FfyF^]l>FaoFfwYFjy>Ffw-%9dsolve/numeric/SC/IVPvalG6$F8Fao7$Fet-Fgt6 $/Fjt&FfwF[uF`uF/F/F/@$4-Feo6$F2Fgo@)-FU6$F2F\\pO-F8F5/F2Q.procedureli stF/O-F[t6#F80Fep%(unknownGOFcpC$>Far-%(pointtoG6#&-F86#FKFiwO-.FarF5> F\\u7#-%*traperrorG6#F]`l@%-Feo6$&F\\uFbq%'stringGY-FgsF[u-Fbs6#&FialF iwF/F/F/" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 125 "In the plot command \+ we need to put quotes around theta(t), as the expression can only be e valuated for numerical values of t." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 27 "plot('theta(t)',t=0..2*Pi);" }}{PARA 13 "" 1 "" {GLPLOT2D 695 299 299 {PLOTDATA 2 "6%-%'CURVESG6$7jn7$$\"\"!F)$\"+![U@ 0$!\"*7$$\"+&eb&p8!#5$\"+OMjVIF,7$$\"+w&)>hDF0$\"+$o87-$F,7$$\"+]dK,RF 0$\"+(=S^(HF,7$$\"+dhL]_F0$\"+]aC)*GF,7$$\"+`\\$Hf'F0$\"+)4,wx#F,7$$\" +,fpPyF0$\"+)[>$3EF,7$$\"+jPdE\"*F0$\"+#)e0\\BF,7$$\"+4L&f/\"F,$\"+B` \"f&>F,7$$\"+MvQ76F,$\"+hD*3q\"F,7$$\"+g<#)y6F,$\"+)3mBS\"F,7$$\"+Fv:Z 7F,$\"+k,N]5F,7$$\"+%H$\\:8F,$\"+_tj$e'F07$$\"+uMov8F,$\"+#)G+$*GF07$$ \"+bO(eV\"F,$!+\\K([**)!#67$$\"+UNj.:F,$!+?4\"R7&F07$$\"+IMRr:F,$!+u%Q r7*F07$$\"+Y:VR;F,$!+:mky7F,7$$\"+i'puq\"F,$!+!RM2g\"F,7$$\"+%*p.tF,$!+HE;7CF,7$$\"+v\")G*4# F,$!+;IzpEF,7$$\"+1GC>AF,$!+ite9GF,7$$\"+f&y(eBF,$!+v0GDHF,7$$\"+V8H#[ #F,$!+2ZQ()HF,7$$\"+VW!yh#F,$!+2WZGIF,7$$\"+h\\%ou#F,$!+WK(z/$F,7$$\"+ ._[\")GF,$!+jE^^IF,7$$\"+wp70IF,$!+$R=-/$F,7$$\"+K8\\QJF,$!+S'o.,$F,7$ 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of~%1,~probably~a~singularityF/F_zFe\\lY6$Qbqcannot~evaluate~the~solut ion~further~left~of~%1,~maxfun~limit~exceeded~(see~?dsolve,maxfun~for~ details)F/F_zFi\\lC$@$F\\]l-F_]l6#-Fb]l6%Qgocannot~evaluate~the~soluti on~further~left~of~%1,~stop~condition~#%2~violatedF/F_zFg]l>F]pF_xYFcz >F_x-%9dsolve/numeric/SC/IVPvalG6$F8F]p7$F_u-Fau6$/Fdu&F_xFeuFjuF/F/F/ @$4-Fap6$F2Fcp@)-F]o6$F2FhpO-F8F5/F2Q.procedurelistF/O-Fet6#F80Faq%(un knownGOF_qC$>F[s-%(pointtoG6#&-F86#FKFerO-.F[sF5>Ffu7#-%*traperrorG6#F f`l@%-Fap6$&FfuF^r%'stringGY-FatFeu-F\\t6#&FbblFerF/F/F/" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 27 "plot('Omega(t)',t=0..2*Pi);" }} {PARA 13 "" 1 "" {GLPLOT2D 695 299 299 {PLOTDATA 2 "6%-%'CURVESG6$7fo7 $$\"\"!F)F(7$$\"+&eb&p8!#5$!+K(y=E\"F-7$$\"+w&)>hDF-$!+hW6XDF-7$$\"+]d K,RF-$!+`*QCV%F-7$$\"+dhL]_F-$!+u/aOrF-7$$\"+`\\$Hf'F-$!+3HA46!\"*7$$ \"+,fpPyF-$!+$\\!GU;FD7$$\"+jPdE\"*F-$!+-(4ZU#FD7$$\"+FM0$z*F-$!+g/@PH FD7$$\"+4L&f/\"FD$!+arIANFD7$$\"+MvQ76FD$!+ReQiTFD7$$\"+g<#)y6FD$!+#4$ 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A \+ useful exercise would be to reduce the parameter " }{TEXT 265 1 "k" } {TEXT -1 137 ", and to observe when the relationship between angular v elocity and angle returns to that of a harmonic oscillator (sine/cosin e curves). " }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 65 "We can also look a t the solutions where the pendulum bob rotates." }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 40 "theta:=(t,k)->2*JacobiAM(sqrt(g/l)*t,k);" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%&thetaGf*6$%\"tG%\"kG6\"6$%)operator G%&arrowGF),$-%)JacobiAMG6$*&-%%sqrtG6#*&%\"gG\"\"\"%\"lG!\"\"F79$F79% \"\"#F)F)F)" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "g:=10; l:=1; " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"gG\"#5" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"lG\"\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 32 "plot(Re(theta(t,0.6*I)),t=0..4);" }}{PARA 13 "" 1 "" {GLPLOT2D 696 299 299 {PLOTDATA 2 "6%-%'CURVESG6$7co7$$\"\"!F)F(7$$\"+m;')=()!#6 $\"+;d4Rb!#57$$\"+e'40j\"F0$\"+W)zo/\"!\"*7$$\"+<6m$[#F0$\"+b*oCi\"F67 $$\"+(>%F0$\"+G@&*\\GF67$$\"+\">K'*)\\F0$ \"+K&yQV$F67$$\"+Dt:5eF0$\"+G^pJSF67$$\"+\"fX(emF0$\"+u6lIYF67$$\"+DCh /vF0$\"+Kbq-_F67$$\"+L/pu$)F0$\"+o%*4odF67$$\"+CI(yv)F0$\"+_0:7gF67$$ \"+;c0T\"*F0$\"+SGzaiF67$$\"+=k,o\"*F0$\"+sY%=F'F67$$\"+@s(\\>*F0$!+5W ZxiF67$$\"+B!Q>A*F0$!+GFUgiF67$$\"+E))*)[#*F0$!+]/PViF67$$\"+J/#GI*F0$ !+CBE4iF67$$\"+P?uc$*F0$!+kk9vhF67$$\"+Z_ek%*F0$!+[t(o5'F67$$\"+e%GCd* F0$!+E[`QgF67$$\"+z[6)y*F0$!+5\"=:!fF67$$\"+I,Q+5F6$!+3&yQw&F67$$\"+SX pV5F6$!+kow%[&F67$$\"+]*3q3\"F6$!+Wv%3?&F67$$\"+q=\\q6F6$!+](Rjj%F67$$ \"+fBIY7F6$!+)ybD5%F67$$\"+j$[kL\"F6$!+!H`pW$F67$$\"+`Q\"GT\"F6$!+A0@% )GF67$$\"+s]k,:F6$!+KB'oB#F67$$\"+`dF!e\"F6$!+\">b:o\"F67$$\"+sgam;F6$ !+cE5(4\"F67$$\"+ F6$\"+qC\"*=[F07$$\"+Uc-)*>F6$\"+VKEK5F67$$\"+f`@'3#F6$\"+k,-F;F67$$\" +nZ)H;#F6$\"+7[$p;#F67$$\"+Ky*eC#F6$\"+C].pFF67$$\"+S^bJBF6$\"+=K0+MF6 7$$\"+0TN:CF6$\"+Ys<6SF67$$\"+7RV'\\#F6$\"+M!RZe%F67$$\"+:#fke#F6$\"++ n\"[>&F67$$\"+`4NnEF6$\"+qpH@dF67$$\"+^b`5FF6$\"+[rl'*fF67$$\"+],s`FF6 $\"+a28qiF67$$\"+ze;cFF6$!+)or2G'F67$$\"+4;heFF6$!+WMIliF67$$\"+Qt0hFF 6$!+C[$)\\iF67$$\"+nI]jFF6$!+'[lVB'F67$$\"+EXRoFF6$!+;LU.iF67$$\"+$)fG tFF6$!++VZshF67$$\"++*oIy#F6$!+g]a5hF67$$\"+:=&Gz#F6$!+imb[gF67$$\"+[w T7GF6$!+!**=V#fF67$$\"+zM)>$GF6$!+%)yf*z&F67$$\"+DZwuGF6$!++(fW_&F67$$ \"+qfa)\\5\"F67$$\"+Sv&)zNF6$! +9se4gF07$$\"+GUYoOF6$!+1/\"4u$F-7$$\"+2^rZPF6$\"+5H+`YF07$$\"+sI@KQF6 $\"+TaZ75F67$$\"+2%)38RF6$\"+:@.c:F67$$\"\"%F)$\"+ytol@F6-%'COLOURG6&% $RGBG$\"#5!\"\"F(F(-%+AXESLABELSG6$Q\"t6\"Q!F`bl-%%VIEWG6$;F(Faal%(DEF AULTG" 1 2 0 1 10 0 2 9 1 4 2 1.000000 45.000000 45.000000 0 0 "Curve \+ 1" }}}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 22 "evalf(theta(1,5.5*I)) ;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#^$$\"+;d)o#e!\"*$!+gI<[>!#>" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 24 "The imaginary values of " }{TEXT 272 1 "k" }{TEXT -1 84 " come from the following analytic continuation of the energy-initial angle relation:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "E_s:=2.1;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$E_sG$ \"#@!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 28 "solve(1-E_s=co s(phi1),phi1);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#^$$\"+aEfTJ!\"*$!+WD oNW!#5" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 17 "k:=evalf(sin(%)); " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"kG^$$!+xVF7X!#>$\"+&pvDe%!#5" }}}{EXCHG {PARA 0 "" 0 "" {TEXT 276 9 "Exercise:" }{TEXT -1 1 " " }} {PARA 0 "" 0 "" {TEXT -1 131 "Adapt the animation to display the motio n in the case where the pendulum bob has sufficient energy to rotate o ver the top position." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" } }}}{MARK "113 1 0" 0 }{VIEWOPTS 1 1 0 1 1 1803 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }