NATS 1750  - The Earth and Its Atmosphere 

                                                                  

Lectures  about 19 to 24

 

                  

Water in the Atmosphere

 

To understand water in the atmosphere and the role it plays in clouds, weather, climate, storms, etc., we need to clarify a few things about pressure.

Pressure is force per unit area - i.e total force/total area it acts on

 

For the atmosphere this force is the total Weight of the air above each square metre of the surface

 

Weight is somewhat different from Mass - Mass is measured in kilograms but Weight should really be measured in Newtons - this difference arises because Weight is the Force that gravity exerts on an object - if we have no gravity we would have no weight but we would  still have our mass - in space we have no gravity so we are weightless even if we still have the same mass - on Earth we have gravity so we have both Weight and Mass

 

The Weight of an object (in Newtons) is given by the Mass of the object (in kilograms) multiplied by 9.8 (this is known as 'g'- the 'acceleration due to gravity')

                                                                                                         

Therefore an object with a mass of 1 kg will have a weight of  9.8 Newtons on Earth

 

The pressure at Earth's surface is really the total Weight of all the air that lies above each square metre of the surface.

 

The total Mass of air over one square metre of Earth's surface is about 10,200 kg (!)

Therefore the Weight of that air is about 100,000 Newtons - i.e 10,200 x 9.8 rounded up

Therefore the Pressure = Weight/Area = 100,000 Newtons m-2

 

Instead of saying 'Newtons per square metre' for pressure we call one Newton m-2 one  'Pascal'

 

Therefore the pressure at Earth's surface is normally about 100,000 Pascals.  Since the normal pressure at the surface can also be expressed as 1000 mbar, this means that  100,000 Pascals is the same as 1000 mbar or 1 mbar = 100 Pascals = 1 hectoPascal

 

Pressure can also be explained as the force exerted by moving gas molecules hitting the sides of an imaginary container - this leads to The Gas Law:

 

P (in Pascals) = r (kg m-3) x R ( Joules kg-1 K-1) x T (K)

 

where r is the density of the gas in kg m-3 and R is the 'Gas Constant'

 

The Gas 'Constant', R, is different for each gas but 'a constant' for that gas

 

For pure dry air (20% O2 and 80% N2) the Gas Constant is R = 287 Joules kg-1 K-1

                     

Changes of State

 

Water can exist in three different 'phases' - solid (ice), liquid (liquid water - 'water') and gas (water vapour)

 

ICE > liquid WATER  latent heat of fusion is absorbed =3.5x105 Joules kg-1

liquid WATER >WATER VAPOUR latent heat of vaporization is absorbed = 2.2x106 Joules kg-1

 

liquid WATER >ICE  latent heat of fusion is released = 3.5x105 Joules kg-1

WATER VAPOUR > liquid WATER latent heat of vaporization is released =2.2x106  Joules kg-1

 

ICE>WATER VAPOUR  latent heat of sublimation is absorbed = 2.8x106 Joules kg-1

WATER VAPOUR>ICE latent heat of sublimation is released = 2.8x106  Joules kg-1

 

Heat is also absorbed (required) to increase the temperature of any substance without it changing phase

 

This is the Specific Heat of the substance

 

The Specific Heat, represented by the symbol C, is the energy that must be supplied to raise the temperature of one kilogram of the material by one degree C

 

For liquid water C = 4180 Joules kg-1 K-1

 

 

Humidity – Water Vapour in Air

 

Water can evaporate at temperatures below the boiling point of 100 ° C

 

This leads to the concept of water's Saturation Vapour Pressure - the SVP

 

If liquid water starts with a vacuum  - i.e., no gas above it - water molecules will leave the liquid to form a gas above. Some of these water vapour molecules will be recaptured by the liquid until an EQUILIBRIUM is established.  At this equilibrium the number of molecules escaping from the liquid will be exactly the same as the number being re-captured and the water molecules (existing as a gas i.e. water vapour) will have some equilibrium pressure - this pressure will depend on the temperature of the liquid water and it is known as the Saturation Vapour Pressure (SVP) over water at that particular temperature.

 

The SVP over liquid water varies with temperature - getting larger at higher temperatures

 

At 0 ° C the SVP over water is 6 mb; at 30 ° C it is 40 mb; at 40 ° C it is 70 mb and at 100 ° C  it is 1000 mb.

 

If we have air with a water vapour pressure greater than the SVP for its temperature the water vapour will condense to reduce its vapour pressure to its SVP

 

If we have air over water with a water vapour pressure less than the SVP for its temperature the liquid water will evaporate to increase its water vapour pressure until it reaches its SVP

 

Since the SVP changes greatly with temperature the amount of water vapour present in air is also highly variable

 

The amount of water vapour present in any sample of air is described by the 'humidity' of that air

 

The humidity of air may be expressed in several ways:

 

Absolute Humidity = gms of water vapour per cubic metre of air, i.e. gm (water) / m3 (air)

Specific Humidity = gms of water per kilogram of air, i.e gm (water)/ kg (air)

Relative Humidity = [pressure of water vapour (mb)/ SVP of water at that temperature (mb)] x 100 %

 

The Relative Humidity can also be expressed in terms of the Water Vapour Capacity of air at that temperature - expressed in terms of gms of water vapour per kilogram of air

 

 i.e. when fully saturated at 40 ° C one kilogram of air can hold 47 gm of water vapour

       when fully saturated at 20 ° C one kilogram of air can hold 14 gm of water vapour

       when fully saturated at 10 ° C one kilogram of air can hold 7  gm of water vapour

       when fully saturated at  0 ° C one kilogram of air can hold 3.5  gm of water vapour

 

Therefore air at 20 ° C containing only 7 gm of water vapour per kilogram has a Relative Humidity of 50% since at 100% RH it could contain 14 gm

 

Therefore if we start off with air that is unsaturated, i.e. RH less than 100% and cool it then as its temperature drops it will eventually become saturated at some point (i.e. when its RH=100%) and the water vapour will start to condense since its RH cannot exceed 100%.   The temperature at which it would start to condense if cooled is known as its Dew Point Temperature.

 

Define Dew Point Temperature, Td (°C) and Wet Bulb Temperature, Twb (°C)

 

The Td (°C) is the temperature the air would have to be cooled to in order to make it's water vapour condense

 

We could measure Td by cooling air and watching when it condenses

 

From the temperature of the air T and Td we can work out its Specific Humidity 'w' and its Relative Humidity R.H.

 

Air at T=20°C with a Td of 10°C has a R.H. of 50%.  This comes from the tables identified in Assignment 2.

 

Air at 10°C has w =7 gm/kg when saturated - air at 25°C would have w = 14 gm/kg when saturated, therefore R.H.= 7/14  x 100% = 50%

 

For two samples of air at same temperature the one with the lower Td has lower R.H.

 

For condensing, i.e. saturated air, its Td is same as its T

 

The Wet Bulb temperature is the temperature to which the air would cool if we let water evaporate into it without supplying any heat.

 

Twb lies between Td and actual temperature T, i.e., Td  <  Twb < T

 

Twb is measured using a Psychrometer - double thermometer with one bulb - the wet bulb - covered with wet cloth. 

The difference between the actual T (the dry bulb temperature) and Twb, ie T-Twb, is called the Depression of the Wet Bulb.

 

From the measured T-Twb and T, the tables of Assignment 2 can be used to determine the R.H. and the Dew Point temperature of the air.  From these the specific humidity can also be determined.

 

For example, if Twb=14°C and T dry = 20°C, then depression of wet bulb is 6 °C and the tables of Assignment 2 give R.H. =51% and Td = 10 °C.

 

For very humid air Twb will only be slightly below T.

 

The Basis of Cloud Formation

 

 

Clouds will, or will not, form depending on the humidity of the air and the temperature structure of the local atmosphere.

 

T usually decreases with height in troposphere.  The decrease in T with height is called the Environmental Lapse Rate, Ge (gamma e).

 

GE is the decrease in T for an increase of 1 km in height

 

If  T decreasing by 12 °C per kilometer then GE = 12 °C/km

If T happens to be decreasing by only 5 °C per kilometer then GE = 5 °C/km

 

The Environmental Lapse Rate, GE, usually changes from place to place and also with height over any one location.

 

Another lapse rate is the Dry Adiabatic Lapse Rate (DALR) or GD.

 

This describes how the temperature of a parcel of uncondensing air would decrease if we raised it up through the atmosphere.  If we let air expand and do not supply heat to it, it will cool ADIABATICALLY.  If we compress air, and do not remove heat from it, it will heat up. Uncondensing air will cool upon lifting at the DALR if we lift it up. 

 

 GD= g/Cp and has a fixed value of 10 °C/km

 

If we raise saturated air up it will also want to cool at the DALR but the latent heat released from the condensing water vapour will provide some extra heat so it will cool less quickly than if it were not condensing and saturated.

 

Saturated, i.e. condensing, air will cool at the Wet Adiabatic Lapse Rate (WALR) given by the symbol GW.  The value of GW depends on the specific humidity of the condensing air.  For warm condensing air GW is about 5°C/km.  For cold condensing air GW is about 9°C/km.

 

i.e. GW = 5 - 9 °C/km

 

If we have air at 32 °C at the surface with a Tdew of 2 °C and we lift it up to 1 km it will cool at DARL to 22 °C and its T will still be greater than its Tdew so it will not condense.

 

 

If we lift it to 2 km it will cool another 10 °C to 12 °C and still not condense.

 

But if we lift it to 3 km it will cool to 2 °C.  Here it will be just at its Tdew and so start to condense and form a cloud

 

The height at which it first condenses is called the CONDENSATION LEVEL

 

If we keep lifting it up it will now cool at the WALR so at 4 km up it will have cooled to -3°C if GW = 5 °C/km.  

 

But how can we lift air to make it form a cloud?

 

Air can lift itself because of Archimedes Principle - if something is less dense than its surroundings it will experience an upward BUOYANCY FORCE acting against gravity.

 

If air is warmer than its surroundings it will be less dense than its surroundings and so will want to rise on its own (just like a hot air balloon) - this air is unstable.

 

 

Reading:

 

TL&T 13th edition, Ch. 17., Waters Changes of State , p. 490-492

 

'Water's Changes of State, 11th p466-468; 10th p434-436(9th p406-407)

'Humidity: Water Vapor in the Atmosphere', 11th p468-473 ;10th p436-441 (9th p407-412)

'Understanding Air Pressure', 11th p502 ;10th p470 (9th 442)

 

TL&T 13th edition, Ch. 17., Humidity: Water Vapor in the Air. p. 492-495

                                                        

'Humidity: Water Vapor in the Atmosphere', 11th p468-473 ;10th p436-441 (9th p407-412)

 

TL&T 13th edition, Ch. 17., Measuring Humidity. p. 496-498

 

TL&T 13th edition, Ch. 17., The Basis of Cloud Formation p. 498-500