{VERSION 4 0 "IBM INTEL NT" "4.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 1 }{CSTYLE "2D Input" 2 19 "" 0 1 255 0 0 1 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 256 "" 1 16 0 0 0 0 0 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 257 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 258 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 259 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 260 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 } {CSTYLE "" -1 261 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 262 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 263 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 264 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 265 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 } {CSTYLE "" -1 266 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 267 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 268 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 269 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 270 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 } {CSTYLE "" -1 271 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 272 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 273 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 274 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 275 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 } {CSTYLE "" -1 277 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 278 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 280 "" 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 281 "" 1 12 0 0 0 0 0 0 0 0 0 0 0 0 0 0 }{PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Heading 1" -1 3 1 {CSTYLE "" -1 -1 "Times" 1 18 0 0 0 1 2 1 2 2 2 2 1 1 1 1 } 1 1 0 0 8 4 1 0 1 0 2 2 0 1 }{PSTYLE "Warning" -1 7 1 {CSTYLE "" -1 -1 "Courier" 1 10 0 0 255 1 2 2 2 2 2 1 1 1 3 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Maple Output" -1 11 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 3 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Map le Output" -1 12 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 3 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Maple Plot" -1 13 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 1 0 0 0 0 1 0 1 0 2 2 0 1 }} {SECT 0 {EXCHG {PARA 0 "" 0 "" {TEXT 256 40 "The work integral in clas sical mechanics" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 103 "Let us demonstrate the path independence of the work int egral for a conservative curl-free force field," }}{PARA 0 "" 0 "" {TEXT -1 44 "such as the gravitational field of a sphere." }}{PARA 0 " " 0 "" {TEXT -1 58 "Let us define the potential energy for a particle \+ of mass " }{TEXT 258 1 "m" }{TEXT -1 46 " in the field of the star (or planet) of mass " }{TEXT 257 1 "M" }{TEXT -1 1 "." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "V:=-G*M*m/r;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"VG,$*&*(%\"GG\"\"\"%\"MGF)%\"mGF)F)%\"rG!\"\"F-" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 13 "with(linalg):" }}{PARA 7 "" 1 "" {TEXT -1 80 "Warning, the protected names norm and trace have been red efined and unprotected\n" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "F:=-grad(V,[x,y,z]);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"FG,$-%'ve ctorG6#7%\"\"!F*F*!\"\"" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 17 "That d idn't work!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 43 "F:=-grad(V,[ r,theta,phi],coords=spherical);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>% \"FG,$-%'vectorG6#7%*&*(%\"GG\"\"\"%\"MGF-%\"mGF-F-*$)%\"rG\"\"#F-!\" \"\"\"!F5F4" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "evalm(F[1]); " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#&,$-%'vectorG6#7%*&*(%\"GG\"\"\"% \"MGF,%\"mGF,F,*$)%\"rG\"\"#F,!\"\"\"\"!F4F36#F," }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 181 "The - sign on front of the grad throws Maple off, because the grad procedure returns a vector, and not a list. The fix \+ is to put the minus sign with the scalar potential function V." }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 43 "F:=grad(-V,[r,theta,phi],coo rds=spherical);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"FG-%'vectorG6#7 %,$*&*(%\"GG\"\"\"%\"MGF-%\"mGF-F-*$)%\"rG\"\"#F-!\"\"F4\"\"!F5" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 5 "F[1];" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,$*&*(%\"GG\"\"\"%\"MGF'%\"mGF'F'*$)%\"rG\"\"#F'!\"\"F. " }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 85 "OK, Maple has its peculiar fe atures! It didn't like the '-' sign before the gradient." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 39 "curl(F,[r,theta,phi],coords=spheric al);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#-%'vectorG6#7%\"\"!F'F'" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 90 "The force field is curl-free by co nstruction: it has been derived from a scalar potential." }}{PARA 0 " " 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 132 "For plotting the \+ potential energy we need to switch to Cartesian coordinates. 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2DAB1AB5DB26BFCADD641D8114F9BFCA5D8E901FAD9CBFC9B6001CDFE531BFC8EFD903 1F6F35BFC81459C53FF0AEBFC72C000B101E41BFC63E0030F579A2BFC55012CDC31B76 BFC4667E78FF99C9BFC384442E05C1C4BFC2AB59D92B962FBFC1EC70124E98F9BFC2AB 59D92B962FBFC37038CB24744CBFC4390861AA78CFBFC502F49F9D6955BFC5CA3BC0E0 92E4BFC68A1F80D71818BFC73CF2A377B47FBFC7DC50378E0408BFC8618618618619BF C8C6318C6318C7BFC904FC246766CBBFC91A556151761CBFC904FC246766CBBFC8C631 8C6318C7BFC8618618618619BFC7DC50378E0408BFC73CF2A377B47FBFC68A1F80D718 18BFC5CA3BC0E092E4BFC502F49F9D6955BFC4390861AA78CFBFC37038CB24744CBFC2 AB59D92B962FBFC1EC70124E98F9-%+AXESLABELSG6%%\"xG%\"yGQ!6\"-%*AXESSTYL EG6#%$BOXG" 1 2 0 1 10 0 2 1 1 2 2 1.000000 45.000000 45.000000 0 0 "C urve 1" }}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 35 "Let us choose a straig ht-line path:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 13 "r_i:=[2,2, 1];" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$r_iG7%\"\"#F&\"\"\"" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "r_f:=[-2,0,1];" }}{PARA 11 " " 1 "" {XPPMATH 20 "6#>%$r_fG7%!\"#\"\"!\"\"\"" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 21 "r_t:=r_i+(r_f-r_i)*t;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$r_tG,&7%\"\"#F'\"\"\"F(*&7%!\"%!\"#\"\"!F(%\"tGF(F( " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 11 "evalm(r_t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#-%'vectorG6#7%,&\"\"#\"\"\"*&\"\"%F)%\"tGF)! \"\",&F(F)*&F(F)F,F)F-F)" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 120 "Note : here t is a parameter, not necessarily time. Nevertheless, we call t he derivative of the parameter representation " }{TEXT 264 1 "v" } {TEXT -1 3 "_t:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 17 "v_t:=dif f(r_t,t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$v_tG7%!\"%!\"#\"\"!" } }}{EXCHG {PARA 0 "" 0 "" {TEXT -1 81 "Now the work integral is reduced to a parameter integral using the dotproduct of " }{TEXT 263 1 "F" } {TEXT -1 6 " with " }{TEXT 262 1 "v" }{TEXT -1 28 "_t, but also realiz ing that " }{TEXT 261 1 "F" }{TEXT -1 38 " needs to be evaluated along the path," }}{PARA 0 "" 0 "" {TEXT -1 9 "i.e., as " }{TEXT 260 1 "F" }{TEXT -1 1 "(" }{TEXT 259 1 "r" }{TEXT -1 7 "_t) !!!" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 228 "Also: we have defined the parameter representation in Cartesian coordinates, so we should u se these coordinates for the dot product calculation, which means that the force has to be translated into Cartesians. How do we do this?" } }{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 46 "F:=grad(-subs(r=sqrt(x^2+y^2+z^2),V),[x,y,z]);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"FG-%'vectorG6#7%,$*&**%\"GG\"\"\"%\"MGF-%\"mGF-% \"xGF-F-*$),(*$)F0\"\"#F-F-*$)%\"yGF6F-F-*$)%\"zGF6F-F-#\"\"$F6F-!\"\" F?,$*&**F,F-F.F-F/F-F9F-F-*$)F3#F>F6F-F?F?,$*&**F,F-F.F-F/F-FF6F-F?F?" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 56 "We start with the common mistake made by many beginners:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 33 "Work:=int(dotprod(F,v_t),t=0..1);" }}{PARA 11 "" 1 " " {XPPMATH 20 "6#>%%WorkG,&*&**%\"GG\"\"\"%\"MGF)%\"mGF)%\"xGF)F)*$),( *$)F,\"\"#F)F)*$)%\"yGF2F)F)*$)%\"zGF2F)F)#\"\"$F2F)!\"\"\"\"%*&*,F2F) F(F)F*F)F+F)F5F)F)*$)F/#F:F2F)F;F)" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 41 "This is a bad answer for several reasons:" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 85 "1) the work has to come o ut as a number (we have specified initial and final points)." }}{PARA 0 "" 0 "" {TEXT -1 57 "2) we have not evaluated the force along the ch osen path." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 16 "r_t:=evalm(r_ t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$r_tG-%'vectorG6#7%,&\"\"#\" \"\"*&\"\"%F+%\"tGF+!\"\",&F*F+*&F*F+F.F+F/F+" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 66 "Work:=int(dotprod(subs(x=r_t[1],y=r_t[2],z=r_t[3 ],F),v_t),t=0..1);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%WorkG,&*&**% \"GG\"\"\"%\"MGF)%\"mGF)%\"xGF)F)*$),(*$)F,\"\"#F)F)*$)%\"yGF2F)F)*$)% \"zGF2F)F)#\"\"$F2F)!\"\"\"\"%*&*,F2F)F(F)F*F)F+F)F5F)F)*$)F/#F:F2F)F; F)" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 90 "This is frustrating: we do \+ apparently the right thing, yet we get the same wrong answer!!!" }} {PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 29 "How do we avoid this pitfall?" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 " " {TEXT -1 73 "1) look at subexpressions, and then realize that someth ing hasn't worked." }}{PARA 0 "" 0 "" {TEXT -1 77 "Substitutions into \+ vectors and matrices in Maple require the use of the op():" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 52 "dotprod(subs(x=r_t[1],y=r_t[2],z=r_ t[3],op(F)),v_t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,&*&**%\"GG\"\"\" %\"MGF'%\"mGF',&!\"\"F'*&\"\"#F'%\"tGF'F'F'F'*$),(\"\"*F'*&\"#CF'F.F'F +*&\"#?F')F.F-F'F'#\"\"$F-F'F+!\")*&*,\"\"%F'F&F'F(F'F)F',&F+F'F.F'F'F '*$)F1#F9F-F'F+F+" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 55 "This is the \+ correct integrand: it no longer depends on " }{TEXT 268 1 "x" }{TEXT -1 2 ", " }{TEXT 267 1 "y" }{TEXT -1 2 ", " }{TEXT 266 1 "z" }{TEXT -1 24 " just on the parameter " }{TEXT 265 1 "t" }{TEXT -1 1 "." }} {PARA 0 "" 0 "" {TEXT -1 20 "Now do the integral:" }}}{EXCHG {PARA 0 " > " 0 "" {MPLTEXT 1 0 70 "Work:=int(dotprod(subs(x=r_t[1],y=r_t[2],z=r _t[3],op(F)),v_t),t=0..1);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%WorkG ,&**-%%sqrtG6#\"\"&\"\"\"%\"GGF+%\"MGF+%\"mGF+#F+F**&#F+\"\"$F+*(F,F+F -F+F.F+F+!\"\"" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 83 "An alternative \+ to using op() is to convert the vector produced by grad into a list." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "FL:=convert(F,list);" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%#FLG7%,$*&**%\"GG\"\"\"%\"MGF*%\"mGF *%\"xGF*F**$),(*$)F-\"\"#F*F**$)%\"yGF3F*F**$)%\"zGF3F*F*#\"\"$F3F*!\" \"F<,$*&**F)F*F+F*F,F*F6F*F**$)F0#F;F3F*F " 0 "" {MPLTEXT 1 0 67 "Work:=int (dotprod(subs(x=r_t[1],y=r_t[2],z=r_t[3],FL),v_t),t=0..1);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%WorkG,&**-%%sqrtG6#\"\"&\"\"\"%\"GGF+%\"M GF+%\"mGF+#F+F**&#F+\"\"$F+*(F,F+F-F+F.F+F+!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "evalf(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#, $*(%\"GG\"\"\"%\"MGF&%\"mGF&$\"+BE!)Q6!#5" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 78 "The work integral tells us by how much the kinetic energy has changed between " }{TEXT 271 1 "r" }{TEXT -1 7 "_i and " }{TEXT 270 1 "r" }{TEXT -1 45 "_f due to the work done by the force on mass \+ " }{TEXT 269 1 "m" }{TEXT -1 1 "." }}{PARA 0 "" 0 "" {TEXT -1 68 "Now \+ let us compare this result with the potential energy difference:" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 4 "r_i;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#7%\"\"#F$\"\"\"" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 69 "We need a function to calculate the magnitude of the position vector: " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 35 "v_mag:=v->sqrt(add(v[i] ^2,i=1..3));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&v_magGR6#%\"vG6\"6$ %)operatorG%&arrowGF(-%%sqrtG6#-%$addG6$*$)&9$6#%\"iG\"\"#\"\"\"/F7;F9 \"\"$F(F(F(" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 22 "v_mag(r_i),v _mag(r_f);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6$\"\"$*$-%%sqrtG6#\"\"&\" \"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 42 "subs(r=v_mag(r_i),V )-subs(r=v_mag(r_f),V);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,&**-%%sqrt G6#\"\"&\"\"\"%\"GGF)%\"MGF)%\"mGF)#F)F(*&#F)\"\"$F)*(F*F)F+F)F,F)F)! \"\"" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 180 "We recognize that the di fference between the potential energy at the initial and final points \+ amounts to the same as the work done on the particle, or the change in kinetic energy." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 7 "Work-%; " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#\"\"!" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 16 "with(plottools);" }}{PARA 12 "" 1 "" {XPPMATH 20 "6 #7F%$arcG%&arrowG%'circleG%%coneG%'cuboidG%&curveG%&cutinG%'cutoutG%)c ylinderG%%diskG%-dodecahedronG%(ellipseG%,ellipticArcG%+hemisphereG%+h exahedronG%*homothetyG%*hyperbolaG%,icosahedronG%%lineG%+octahedronG%) piesliceG%&pointG%(polygonG%(projectG%*rectangleG%(reflectG%'rotateG%& scaleG%*semitorusG%'sphereG%)stellateG%,tetrahedronG%&torusG%*transfor mG%*translateG%%vrmlG" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 80 "l \+ := line(r_i, r_f, color=red, linestyle=2, thickness=3): plots[display] (l,PL1);" }}{PARA 13 "" 1 "" {GLPLOT3D 400 300 300 {PLOTDATA 3 "6&-%'C URVESG6&7$7%$\"\"#\"\"!F($\"\"\"F*7%$!\"#F*$F*F*F+-%*THICKNESSG6#\"\"$ -%*LINESTYLEG6#F)-%'COLOURG6&%$RGBG$\"*++++\"!\")F0F0-%%GRIDG6%;$!\"&F 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9A2BFC55012CDC31B76BFC4667E78FF99C9BFC384442E05C1C4BFC2AB59D92B962FBFC 1EC70124E98F9BFC2AB59D92B962FBFC37038CB24744CBFC4390861AA78CFBFC502F49 F9D6955BFC5CA3BC0E092E4BFC68A1F80D71818BFC73CF2A377B47FBFC7DC50378E040 8BFC8618618618619BFC8C6318C6318C7BFC904FC246766CBBFC91A556151761CBFC90 4FC246766CBBFC8C6318C6318C7BFC8618618618619BFC7DC50378E0408BFC73CF2A37 7B47FBFC68A1F80D71818BFC5CA3BC0E092E4BFC502F49F9D6955BFC4390861AA78CFB FC37038CB24744CBFC2AB59D92B962FBFC1EC70124E98F9-%+AXESLABELSG6%%\"xG% \"yGQ!6\"-%*AXESSTYLEG6#%$BOXG" 1 2 0 1 10 0 2 1 1 2 2 1.000000 45.000000 45.000000 0 0 "Curve 1" "Curve 2" }}}}{EXCHG {PARA 0 "" 0 " " {TEXT -1 159 "As the particle traverses the potential well it picks \+ up a lot of kinetic energy on the way down, in order to give up a good fraction as it climbs up the hill." }}{PARA 0 "" 0 "" {TEXT -1 0 "" } }{PARA 0 "" 0 "" {TEXT -1 75 "We can verify this by calculating the wo rk done at some intermediate point." }}{PARA 0 "" 0 "" {TEXT -1 43 "Fi rst recall the total kinetic energy gain:" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 12 "evalf(Work);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,$* (%\"GG\"\"\"%\"MGF&%\"mGF&$\"+BE!)Q6!#5" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 79 "Now break the path up into two halves, just by looking at what happens between " }{TEXT 275 1 "t" }{TEXT -1 7 "=0 and " }{TEXT 274 1 "t" }{TEXT -1 23 "=0.5, and then between " }{TEXT 273 1 "t" } {TEXT -1 9 "=0.5 and " }{TEXT 272 1 "t" }{TEXT -1 3 "=1:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 73 "Work1:=int(dotprod(subs(x=r_t[1],y= r_t[2],z=r_t[3],op(F)),v_t),t=0..1/2);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&Work1G,&**-%%sqrtG6#\"\"#\"\"\"%\"GGF+%\"MGF+%\"mGF+#F+F**&#F +\"\"$F+*(F,F+F-F+F.F+F+!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 73 "Work2:=int(dotprod(subs(x=r_t[1],y=r_t[2],z=r_t[3],op(F)),v_t),t =1/2..1);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&Work2G,&**-%%sqrtG6#\" \"&\"\"\"%\"GGF+%\"MGF+%\"mGF+#F+F**&#F+\"\"#F+**-F(6#F2F+F,F+F-F+F.F+ F+!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 33 "evalf([Work1,Wor k2,Work1+Work2]);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#7%,$*(%\"GG\"\"\" %\"MGF'%\"mGF'$\"+xWtPP!#5,$F%$!+a=$*)f#F,,$F%$\"+BE!)Q6F," }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 323 "Notice the large amount of work done on \+ the particle on the first 'half', then the particle works against the \+ potential well, but still has a net gain of kinetic energy at the fina l point. It is, however, at a lower value of potential energy at this \+ point, i.e., it gained kinetic energy at the expense of potential ener gy." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 177 "Now consider a non-conservative force. It will have no direct \+ physical meaning, i.e., it is a made-up problem to demonstrate what ha ppens when a force field is not conservative." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }} }{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 29 "F:=[x^2+2*y-z,y+z-x,z^3+x*2 ];" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"FG7%,(*$)%\"xG\"\"#\"\"\"F+* &F*F+%\"yGF+F+%\"zG!\"\",(F-F+F.F+F)F/,&*$)F.\"\"$F+F+*&F*F+F)F+F+" }} }{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 13 "with(linalg):" }}{PARA 7 " " 1 "" {TEXT -1 80 "Warning, the protected names norm and trace have b een redefined and unprotected\n" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 16 "curl(F,[x,y,z]);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#-%'vectorG 6#7%!\"\"!\"$F(" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 132 "This force fi eld is not curl-free, which means that it cannot be derived from a sca lar potential. We choose the same path as before." }}}{EXCHG {PARA 0 " > " 0 "" {MPLTEXT 1 0 13 "r_i:=[2,2,1];" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$r_iG7%\"\"#F&\"\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "r_f:=[-2,0,1];" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$r_fG7%!\"# \"\"!\"\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 28 "r_t:=evalm(r _i+(r_f-r_i)*t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$r_tG-%'vectorG6 #7%,&\"\"#\"\"\"*&\"\"%F+%\"tGF+!\"\",&F*F+*&F*F+F.F+F/F+" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 17 "v_t:=diff(r_t,t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$v_tG\"\"!" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 46 "Another one of these Maple-quirks. We defined " }{TEXT 19 3 "r_t" } {TEXT -1 36 " as a combination of lists, but the " }{TEXT 19 5 "evalm " }{TEXT -1 21 " did something funny." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "whattype(r_t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#%'s ymbolG" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 17 "The evalm turned " } {TEXT 19 3 "r_t" }{TEXT -1 15 " into a symbol." }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 21 "v_t:=map(diff,r_t,t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$v_tG-%'vectorG6#7%!\"%!\"#\"\"!" }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 22 "If we had avoided the " }{TEXT 19 5 "evalm" } {TEXT -1 139 ", the simple differentiation would have worked because t appeared as a factor of one of the lists (as carried out in the previ ous section)." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 69 "Work1:=int (dotprod(subs(x=r_t[1],y=r_t[2],z=r_t[3],F),v_t),t=0..1/2);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&Work1G#!#\\\"\"'" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 69 "Work2:=int(dotprod(subs(x=r_t[1],y=r_t[2],z=r_t[ 3],F),v_t),t=1/2..1);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&Work2G#!#J \"\"'" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 66 "Work:=int(dotprod( subs(x=r_t[1],y=r_t[2],z=r_t[3],F),v_t),t=0..1);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%WorkG#!#S\"\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 38 "evalf([Work1,Work2,Work1+Work2,Work]);" }}{PARA 11 " " 1 "" {XPPMATH 20 "6#7&$!+nmmm\")!\"*$!+nmmm^F&$!+LLLL8!\")F)" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 229 "Of course, the work integral is a dditive. What we want to demonstrate is that if we connect the two end points in some different way, then a different result will be found fo r the work done on the particle as it moves from A to B." }}{PARA 0 " " 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 122 "Let us choose as \+ an alternative to the direct connection from A to B a path that goes v ia the origin [0,0,1] in the plane." }}{PARA 0 "" 0 "" {TEXT -1 0 "" } }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 13 "r_1:=[0,0,1];" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$r_1G7%\"\"!F&\"\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 30 "r_tp1:=evalm(r_i+(r_1-r_i)*t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&r_tp1G-%'vectorG6#7%,&\"\"#\"\"\"*&F*F+%\"tGF+!\" \"F)F+" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 25 "v_tp1:=map(diff,r _tp1,t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&v_tp1G-%'vectorG6#7%!\" #F)\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 30 "r_tp2:=evalm(r_ 1+(r_f-r_1)*t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&r_tp2G-%'vectorG 6#7%,$%\"tG!\"#\"\"!\"\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 25 "v_tp2:=map(diff,r_tp2,t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&v_ tp2G-%'vectorG6#7%!\"#\"\"!F*" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 48 " Now we are ready to calculate the work integral." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 75 "Work1:=int(dotprod(subs(x=r_tp1[1],y=r_tp1[2] ,z=r_tp1[3],F),v_tp1),t=0..1);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&W ork1G#!#?\"\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 75 "Work2:=in t(dotprod(subs(x=r_tp2[1],y=r_tp2[2],z=r_tp2[3],F),v_tp2),t=0..1);" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%&Work2G#!\"#\"\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 26 "evalf([Work1+Work2,Work]);" }}{PARA 11 " " 1 "" {XPPMATH 20 "6#7$$!+LLLLt!\"*$!+LLLL8!\")" }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 109 "The amount work done on the particle as it moves \+ through the force field along a different path is different!" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 77 "What can we do \+ to visualize the force field, and how it affects the particle?" }} {PARA 0 "" 0 "" {TEXT -1 36 "First define the force field in the " } {TEXT 277 1 "z" }{TEXT -1 90 "=1 plane and ignore the z-component of t he force, as we are not moving the particle along " }{TEXT 278 1 "z" } {TEXT -1 51 " (no work is done by this component of the force!)." }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "Fzeq1:=subs(z=1,F);" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%&Fzeq1G7%,(*$)%\"xG\"\"#\"\"\"F+*&F* F+%\"yGF+F+F+!\"\",(F-F+F+F+F)F.,&F+F+*&F*F+F)F+F+" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 25 "F2d:=[Fzeq1[1],Fzeq1[2]];" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$F2dG7$,(*$)%\"xG\"\"#\"\"\"F+*&F*F+%\"yGF+F+F+!\" \",(F-F+F+F+F)F." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "with(pl ots):" }}{PARA 7 "" 1 "" {TEXT -1 50 "Warning, the name changecoords h as been redefined\n" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 98 "PL1: =fieldplot(F2d,x=-2..2,y=-2..2,arrows=thick,color=blue,axes=boxed,grid =[12,12]): 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being curl-free." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 38 "e valf([Work1,Work2,Work1+Work2,Work]);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#7&$!+nmmmm!\"*$F%!#5$!+LLLLtF&$!+LLLL8!\")" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 169 "Note that the amount of work done by the force on the particle is negative. We start the particle at [2,2] (top right-hand \+ corner), and it moves against the force field." }}{PARA 0 "" 0 "" {TEXT -1 278 "The fact that it arrives at location [0,-2] with a negat ive amount of work (it worked against the force field) means that its \+ kinetic energy will be less than it was at A. It will be less at B tha n at A by a different amount depending on whether the red or green pat h is chosen." }}{PARA 0 "" 0 "" {TEXT -1 24 "An interesting question: " }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT 280 9 "Exerc ise:" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 114 " Calculate the work done on the particle along a path such that it gain s energy to go from A=[2,2,1] to B=[-2,0,1]." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{SECT 1 {PARA 3 "" 0 "" {TEXT 281 8 "Solutio n" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "r_i,r_f;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6$7%\"\"#F$\"\"\"7%!\"#\"\"!F%" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "r_1:=[2,-2,1];" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$r_1G7%\"\"#!\"#\"\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 30 "r_tp1:=evalm(r_i+(r_1-r_i)*t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&r_tp1G-%'vectorG6#7%\"\"#,&F)\"\"\"*&\"\"%F+%\"tGF+!\"\"F+" } }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 15 "r_2:=[-2,-2,1];" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$r_2G7%!\"#F&\"\"\"" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 25 "v_tp1:=map(diff,r_tp1,t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&v_tp1G-%'vectorG6#7%\"\"!!\"%F)" }}}{EXCHG {PARA 0 " > " 0 "" {MPLTEXT 1 0 30 "r_tp2:=evalm(r_1+(r_2-r_1)*t);" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 25 "v_tp2:=map(diff,r_tp2,t);" }}{PARA 11 "" 1 " " {XPPMATH 20 "6#>%&r_tp2G-%'vectorG6#7%,&\"\"#\"\"\"*&\"\"%F+%\"tGF+! \"\"!\"#F+" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&v_tp2G-%'vectorG6#7%! \"%\"\"!F*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 30 "r_tp3:=evalm( r_2+(r_f-r_2)*t);" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 25 "v_tp3:=map(dif f,r_tp3,t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&r_tp3G-%'vectorG6#7% !\"#,&F)\"\"\"*&\"\"#F+%\"tGF+F+F+" }}{PARA 11 "" 1 "" {XPPMATH 20 "6# >%&v_tp3G-%'vectorG6#7%\"\"!\"\"#F)" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 48 "Now we are ready to calculate the work integral." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 75 "Work1:=int(dotprod(subs(x=r_tp1[1], y=r_tp1[2],z=r_tp1[3],F),v_tp1),t=0..1);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&Work1G\"\"%" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 75 "Wor k2:=int(dotprod(subs(x=r_tp2[1],y=r_tp2[2],z=r_tp2[3],F),v_tp2),t=0..1 );" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&Work2G#\"#W\"\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 75 "Work3:=int(dotprod(subs(x=r_tp3[1], y=r_tp3[2],z=r_tp3[3],F),v_tp3),t=0..1);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&Work3G\"\"%" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 25 "eva lf(Work1+Work2+Work3);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+nmmmA!\" )" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{MARK "0 0 0" 5 }{VIEWOPTS 1 1 0 1 1 1803 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }